would trigger this useEffect twice: useEffect(() => { console.log('do something as initial state of onChainNFTs changed'); // triggered 2 times }, [onChainNFTs]); I confirmed that the component MOUNTED ONLY ONCE and setOnChainNFTs was NOT called more than once - so this was not the issue. See more This one should be obvious, your component is in the page a couple of times and each one will mount and run the useEffect See more The component is being forced to unmount and remount on its initial render. This could be something like a "key" change happening higher up the tree. you need to go up each … See more This answer was pointed out by @johnhendirx and written by @rangfu, see link and give him some love if this was your problem. If you're having issues because of this it usually means you're not using useEffect for its … See more WebJan 31, 2024 · useEffect(()=>{ constid =setInterval(()=>{ setCount(count +1) },1000) return()=>clearInterval(id) return {count} In the class-based code, the counter increments every second. In the hooks-based component it increments from 0to 1and then stops. But it's interesting to learn that the interval doesn't actuallystop.
reactjs - React Hooks - useEffect fires even though the …
WebApr 7, 2024 · 3. As we all know the useEffect is called once on initial render and also on subsequent change of values of dependency array. In your case, to skip initial execution … WebReact will always flush a previous render’s effects before starting a new update. Conditionally firing an effect The default behavior for effects is to fire the effect after every completed render. That way an effect is always recreated … im on lean i might black out shawty
React core team on the recommended way to build with react
WebApr 10, 2024 · Put a console.log inside the useEffect () to see how many times is firing... 1.- Maybe you have a second instance of that component that's making the same … WebuseEffect(() => { setFullName(firstName + ' ' + lastName); }, [firstName, lastName]); // ... } This is more complicated than necessary. It is inefficient too: it does an entire render pass with a stale value for fullName, then immediately re-renders with the updated value. Remove the state variable and the Effect: function Form() { WebMay 20, 2024 · The useEffect callback in this case runs twice for the initial render. After state change, the component renders twice, but the effect should run once. Example: imoniyame holdings ltd